Q105 / 180 · NEET 2015 (Phase 1) · Physics

A mass m moves in a circle on a smooth horizontal plane with velocity v0 at a radius R0 . The mass is attached to a string which passes through a smooth hole in plane as shown.

Figure


The tension in the string is increased gradually and finally m moves in a circle of radius R02. The final value of the kinetic energy is:

  • A
    mv02
  • B
    14mv02
  • Correct answer
    C
    2 mv02
  • D
    12mv02

Solution

From conservation of angular momentum. \(\begin{aligned} & m v_0 R_0=m v^{\prime}\left(\frac{R_0}{2}\right) \\ & \Rightarrow v^{\prime}=2 v_0 \end{aligned}\) Hence, final \(K E=\frac{1}{2} m v^{\prime 2}=\frac{1}{2} m\left(2 v_0\right)^2\) Final \(KE=2 m v_0^2\)

Hence, the correct answer is option: 'C'.

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