Q105 / 180 · NEET 2015 (Phase 1) · Physics
A mass moves in a circle on a smooth horizontal plane with velocity at a radius . The mass is attached to a string which passes through a smooth hole in plane as shown.

The tension in the string is increased gradually and finally moves in a circle of radius . The final value of the kinetic energy is:
A mass moves in a circle on a smooth horizontal plane with velocity at a radius . The mass is attached to a string which passes through a smooth hole in plane as shown.

The tension in the string is increased gradually and finally moves in a circle of radius . The final value of the kinetic energy is:
- A
- B
- Correct answerC
- D
Solution
From conservation of angular momentum.
\(\begin{aligned}
& m v_0 R_0=m v^{\prime}\left(\frac{R_0}{2}\right) \\
& \Rightarrow v^{\prime}=2 v_0
\end{aligned}\)
Hence, final \(K E=\frac{1}{2} m v^{\prime 2}=\frac{1}{2} m\left(2 v_0\right)^2\)
Final \(KE=2 m v_0^2\)
Hence, the correct answer is option: 'C'.