Q119 / 200 · NEET 2024 (Re-NEET) · Physics
A particle executing simple harmonic motion with amplitude $A$ has the same potential and kinetic energies at the displacement
- A$2 \sqrt{A}$
- B$\frac{A}{2}$
- Correct answerC$\frac{A}{\sqrt{2}}$
- D$A \sqrt{2}$
Solution
Potential energy $=\frac{1}{2} k x^2$
Kinetic energy $=\frac{1}{2} k A^2-\frac{1}{2} k x^2$
According to given condition
$\frac{1}{2} k x^2=\frac{1}{2} k A^2-\frac{1}{2} k x^2$
$k 2 x^2=k A^2$
$x^2=\frac{A^2}{2}$
$x=\frac{A}{\sqrt{2}}$
Hence, the correct answer is option: 'C'.