A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum…

Question

A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is _____ s

MARKS Content Team · Accepted Answer

Correct answer: 1. Given here, A=8 cm and T=6 s The displacement equation in SHM, when amplitude is halved is Acos(2πt)/T=A/2 ⇒(2πt)/T=(π)/3 Time taken by the particle is t= T/6=6/6=1sec.

A particle executes simple harmonic motion. Its amplitude is $8 cm$ and time period is $6 s$ . The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is _____ $s$

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