A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3 V s^(-1). The…

Question

A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3 V s^(-1). The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively:

MARKS Content Team · Accepted Answer

Correct answer: (B) 60 μA, 60 μA. q=CV dq/dt=Cdv/dt =20×10^(-6)×3 Conduction current =60 μA Displacement current =ε_0(dϕ_e)/dt =ε_0A/ddV/dt =60 μA

A parallel plate capacitor of capacitance $20 μ F$ is being charged by a voltage source whose potential is changing at the rate of $3 V s^{- 1}$ . The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively:

Solution

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A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3 V s-1. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively:

Solution

More Capacitance Questions

A parallel plate capacitor of capacitance $20 μ F$ is being charged by a voltage source whose potential is changing at the rate of $3 V s^{- 1}$ . The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively: