Q91 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Mathematics

A number lock has 3 rings and each ring has 8 digits. Total number of different ways in which 3 rings can be rotated is

  • A
    \(3^8\)
  • Correct answer
    B
    \(8^3\)
  • C
    \(3 \times 8\)
  • D
    \({ }^8 P_3\)

Solution

Since, it is given that a lock has 3 rings and each ring has 8 digits, so each ring can be rotated in 8 ways, therefore total number of different ways in which 3 rings can be rotated is \(8 \times 8 \times 8=8^3\). Hence, option (b) is correct.

Hence, the correct answer is option: 'B'.

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