Q182 / 200 · Manipal (MET) 2012 · Physics
A nucleus $X$ initially at rest, undergoes alpha decay according to the equation
$92 X^A \rightarrow{ }_Z Y^{228}+\alpha$
Then, the value of $A$ and $Z$ are
- A94,230
- Correct answerB232,90
- C190,32
- D230,94
Solution
The decay equation is
${ }_{92} X^A \longrightarrow{ }_Z Y^{228}+\alpha$
$\alpha$-particle is nucleus of ${ }_2 \mathrm{He}^4$
$\begin{gathered}
{ }_{92} X^A \longrightarrow{ }_Z Y^{228}+{ }_2 \mathrm{He}^4 \\
A=228+4=232 \\
Z=92-2=90
\end{gathered}$
Hence, the correct answer is option: 'B'.