Q144 / 200 · WBJEE 2013 · Physics

A NOR gate and a NAND gate are connected as shown in the figure. Two different sets of inputs are given to this setup. In the first case, the inputs to the gates are $A=0, B=0$, $C=0 .$ In the second case, the inputs are $A=1, B=0, C=1 .$ The output $D$ in the first case and second case respectively are Figure

  • A
    0 and 0
  • B
    0 and 1
  • C
    1 and 0
  • Correct answer
    D
    1 and 1

Solution

In first case $A=0, B=0$ $\therefore$ Output of NOR gate, $Y=\overline{A+B}=1$ This output is the input for NAND gate, $i . e ., Y=1$ and $C=0$ $\therefore \quad D=\overline{Y \cdot C}=1$ In second case $A=1, B=0$ $\therefore$ Output of NOR gate, $Y=\overline{A+B}=0$ This output is the input for NAND gate $i . e . . Y=0$ and $C=1$ $\therefore \quad D=\overline{Y \cdot C}=1$

Hence, the correct answer is option: 'D'.

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