Q115 / 160 · JIPMER 2005 · Physics
A monoatomic gas supplied the heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be
- Correct answerA$\frac{2}{3} Q$
- B$\frac{3}{5} Q$
- C$\frac{2}{5} Q$
- D$\frac{1}{5} Q$
Solution
For monoatomic gas at constant pressure
$\frac{\Delta U}{Q}=\frac{1}{3}$
or $\quad \Delta U=\frac{Q}{3}$
Now applying first law of thermodynamics
$\begin{aligned} W & =\Delta Q-\Delta U \\ & =Q-\frac{Q}{3}=\frac{2 Q}{3}\end{aligned}$
Hence, the correct answer is option: 'A'.