A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad…

Question

A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s^(-1). If the horizontal component of earth's magnetic field is 0.2×10^(-4) T, then emf induced between the two ends of the conductor is

MARKS Content Team · Accepted Answer

Correct answer: (B) 50μV. Given here, B_H=0.2×10^(-4) T, ω=5 rad s^(-1) and l= 1 m. Emf induced in a rotating conducting rod is given by, ε=1/2Bωl^2 Substituting the given values, we obtain ε=1/2×0.2×10^(-4)×5×1^2=0.5×10^(-4) V=50 μV

A metallic conductor of length $1 m$ rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity $5 rad s^{- 1}$ . If the horizontal component of earth's magnetic field is $0.2 \times 10^{- 4} T$ , then emf induced between the two ends of the conductor is

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Relevant Questions

A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s-1. If the horizontal component of earth's magnetic field is 0.2×10-4 T, then emf induced between the two ends of the conductor is

Solution

Relevant Questions

A metallic conductor of length $1 m$ rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity $5 rad s^{- 1}$ . If the horizontal component of earth's magnetic field is $0.2 \times 10^{- 4} T$ , then emf induced between the two ends of the conductor is