Q78 / 160 · AP EAMCET 2022 (04 Jul Shift 2) · Mathematics

A manager decides to distribute Rs.20000 between two employees X and Y. He knows X deserves more than Y, but does not know how much more. So, he decides to arbitrarily break Rs.20000 in to two parts and gives X the bigger part. Then, the chance that X gets twice as much as Y or more is

  • A
    25
  • B
    12
  • C
    13
  • Correct answer
    D
    23

Solution

Given,

X gets the bigger part than Y

So, the bigger part could be any number from 10000 to 20000.

Now, if the bigger part is to be at least twice as much as the smaller part, we have

X≥2Y

⇒X≥220000-X

⇒X≥400003
So, the probability is equal to 20000-40000/320000-10000=23

Hence the answer is  23

Hence, the correct answer is option: 'D'.

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