Q83 / 150 · MHT CET 2021 (24 Sep Shift 1) · Mathematics
A man is know to speak truth 3 out of 4 times. He throws a die and reports that it is 6 . Then the probability that it is actually 6 is
- A$\frac{3}{4}$
- B$\frac{1}{4}$
- Correct answerC$\frac{3}{8}$
- D$\frac{5}{6}$
Solution
Probability of man speaking truth $=\frac{3}{4} \Rightarrow$ Probability of telling
$$
\text { lies }=\frac{1}{4}
$$
Probability of a die actually showing $6=\frac{\left(\frac{1}{6} \times \frac{3}{4}\right)}{\left(\frac{1}{6} \times \frac{3}{4}\right)+\left(\frac{5}{6} \times \frac{1}{4}\right)}=\frac{3}{8}$
Hence, the correct answer is option: 'C'.