Q99 / 150 · MHT CET 2021 (23 Sep Shift 1) · Mathematics
A die is thrown four times. The probability of getting perfect square in at least one throw is
- A$\frac{58}{61}$
- B$\frac{16}{81}$
- Correct answerC$\frac{65}{81}$
- D$\frac{23}{81}$
Solution
From 1 to 6 , we have 1 and 4 as perfect squares.
Probability of getting perfect square is one throw of a die
$$
=\frac{2}{6}=\frac{1}{3}
$$
$\therefore$ Probability of not getting perfect square in 4 throws of a die
$$
=\frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3}=\frac{16}{81}
$$
$\therefore$ Required probability $=1-\frac{16}{81}=\frac{65}{81}$
Hence, the correct answer is option: 'C'.