A machine gun fires a bullet of mass 40 g with a velocity 1200 m s^(-1). The man holding it can exert a maximum force of 144 N on the gun. The maximum…

Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 m s^(-1). The man holding it can exert a maximum force of 144 N on the gun. The maximum number of bullets that the man can fire per second is

MARKS Content Team · Accepted Answer

Correct answer: 3. Suppose he can fire n bullets per second ∴ Force = Change in momentum per second 144=n⁡×(40/1000)×(1200) n⁡=(144×1000)/(40×1200) n⁡=3

A machine gun fires a bullet of mass $40 g$ with a velocity $1200 m s^{- 1}$ . The man holding it can exert a maximum force of $144 N$ on the gun. The maximum number of bullets that the man can fire per second is

Solution

More Center of Mass Momentum and Collision Questions

A machine gun fires a bullet of mass 40 g with a velocity 1200 m s-1. The man holding it can exert a maximum force of 144 N on the gun. The maximum number of bullets that the man can fire per second is

Solution

More Center of Mass Momentum and Collision Questions

A machine gun fires a bullet of mass $40 g$ with a velocity $1200 m s^{- 1}$ . The man holding it can exert a maximum force of $144 N$ on the gun. The maximum number of bullets that the man can fire per second is