Among H_2, He2+, Li_2, Be_2, B_2 ,C_2, N_2, O2-, and F_2 , the number of diamagnetic species is - (Atomic number : H = 1, He = 2, Li = 3, Be = 4, B =…

Question

Among H_2, He2+, Li_2, Be_2, B_2 ,C_2, N_2, O2-, and F_2 , the number of diamagnetic species is - (Atomic number : H = 1, He = 2, Li = 3, Be = 4, B = 5, C = 6, N = 7, O = 8 , F = 9)

MARKS Content Team · Accepted Answer

Correct answer: 5. H_2 ⇒ σ1s^2 (Diamagnetic) He2+ ⇒ σ1s^(2 ) σ^(*) 1s^1 (Paramagnetic) Li_2 ⇒ σ1s^2 σ^(*) 1s^2 σ2s^2 (Diamagnetic) Be_2 ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 (Does not exist) B_2 ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 π2px1=π2py1 (Paramagnetic) C_2 ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 π2px2=π2py2 (Diamagnetic) N_2 ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 π2px2=π2py2 σ2pz2 (Diamagnetic) O2Θ ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 σ2pz2 π2px2=π2py2 π^(*)2px2=π^(*)2py1 (Paramagnetic) F_2 ⇒ σ1s^2 σ^(*)1s^2 σ2s^2 σ^(*)2s^2 σ2oz2 π2px2=π2py2 π^(*)2px2 =π^(*)2py2 (Diamagnetic)

$A m o n g H_{2}, H e_{2}^{+}, L i_{2}, B e_{2}, B_{2}, C_{2}, N_{2}, O_{2}^{-}, a n d F_{2},$ the number of diamagnetic species is -
(Atomic number : $H = 1, H e = 2, L i = 3, B e = 4, B = 5, C = 6, N = 7, O = 8, F = 9)$

Solution

Relevant Questions

$H_{2} \Rightarrow σ 1 s^{2}$	(Diamagnetic)
$H e_{2}^{+} \Rightarrow σ 1 s^{2}$ $σ^{*} 1 s^{1}$	(Paramagnetic)
$L i_{2} \Rightarrow σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2}$	(Diamagnetic)
$B e_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2}$	(Does not exist)
$B_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{1} = π 2 p_{y}^{1}$	(Paramagnetic)
$C_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2}$	(Diamagnetic)
$N_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} σ 2 p_{z}^{2}$	(Diamagnetic)
$O_{2}^{Θ} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$	(Paramagnetic)
$F_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 o_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{2}$	(Diamagnetic)

Among H2, He2+, Li2, Be2, B2 ,C2, N2, O2-, and F2 , the number of diamagnetic species is -(Atomic number : H = 1, He = 2, Li = 3, Be = 4, B = 5, C = 6, N = 7, O = 8 , F = 9)

Solution

Relevant Questions

$A m o n g H_{2}, H e_{2}^{+}, L i_{2}, B e_{2}, B_{2}, C_{2}, N_{2}, O_{2}^{-}, a n d F_{2},$ the number of diamagnetic species is -
(Atomic number : $H = 1, H e = 2, L i = 3, B e = 4, B = 5, C = 6, N = 7, O = 8, F = 9)$