A long slender rod is welded to a thin circular disc of diameter 0.5 m at a point on its circumference. The rod is in the same plane as that of the…

Question

A long slender rod is welded to a thin circular disc of diameter 0.5 m at a point on its circumference. The rod is in the same plane as that of the disc and forms a tangent to the disc. The radius of gyration of the disc about the rod (in m) is

MARKS Content Team · Accepted Answer

Correct answer: (B) √54. The long slender rod is welded to the thin circular disc of radius R=0.5 m tangential in the plane of disc. Therefore, tangential axis of disc is along the rod. The moment of inertia of disc along the tangential axis in the plane of disc is given by, I=5/4MR^2 Radius of gyration is, K=√IM=√(54MR^2M)=√52R ⇒ K=√52×0.5=√54 m

A long slender rod is welded to a thin circular disc of diameter $0.5 m$ at a point on its circumference. The rod is in the same plane as that of the disc and forms a tangent to the disc. The radius of gyration of the disc about the rod (in $m$ ) is

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