Q84 / 100 · BITSAT 2024 (Memory Based Paper 2) · Physics
A light string passing over a smooth light pulley connects two blocks of masses $\mathrm{m}_1$ and $\mathrm{m}_2$ (where $m_2 \gt m_1$). If the acceleration of the system is $\frac{\mathrm{g}}{\sqrt{2}}$, then the ratio of the masses $\frac{m_1}{m_2}$ is:
- Correct answerA$\frac{\sqrt{2}-1}{\sqrt{2}+1}$
- B$\frac{1+\sqrt{5}}{\sqrt{5}-1}$
- C$\frac{1+\sqrt{5}}{\sqrt{2}-1}$
- D$\frac{\sqrt{3}+1}{\sqrt{2}-1}$
Solution
Acceleration is given as:
$a=\left(\frac{m_2-m_1}{m_1+m_2}\right) g$
$\Rightarrow \frac{\mathrm{g}}{\sqrt{2}}=\left(\frac{\mathrm{m}_2-\mathrm{m}_1}{\mathrm{~m}_1+\mathrm{m}_2}\right) \mathrm{g}$
$\Rightarrow \sqrt{2}\left(m_2-m_1\right)=m_1+m_2$
$\Rightarrow \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\left(\frac{\sqrt{2}-1}{\sqrt{2}+1}\right)$
Hence, the correct answer is option: 'A'.