A light rod of length, $l$ has two masses, $m_1$ and $m_2$ attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

• Correct answer
  A

  $\frac{m_1{m}_2}{m_1+m_2}{l}^2$
• B

  $\frac{m_1+m_2}{m_1{m}_2}{l}^2$
• C

  $\left(m_1+m_2\right)l^2$
• D

  $\sqrt{m_1{m}_2}{l}^2$

Hence, the correct answer is option: 'A'.