A large conducting slab having uniform surface charge density is placed between a parallel plate capacitor as shown in the figure. The net surface charge density on the slab after its placement in between the capacitor plates is $+\sigma / 2$. The surface charge density on capacitor plates are $\pm \sigma$. Assuming equal cross-sectional area of capacitor plates and the slab, the induced surface charge density on the conducting slab surface facing the positive terminal of the capacitor is

• A

  $-\sigma$
• B

  $-5 \sigma / 4$
• C

  $-\sigma / 4$
• Correct answer
  D

  $-3 \sigma / 4$

Hence, the correct answer is option: 'D'.