Q220 / 270 · NDA 2016 (Phase 2) · Mathematics
A force $\vec{F}=3 \hat{i}+2 \hat{j}-4 \hat{k}$ is applied at the point $(1,-1,2)$. What is the moment of the force about the point $(2,-1,3)$ ?
- A$\hat{\mathrm{i}}+4 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}$
- B$2 \hat{i}+\hat{j}+2 \hat{k}$
- Correct answerC$2 \hat{i}-7 \hat{j}-2 \hat{k}$
- D$2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-\hat{\mathrm{k}}$
Solution
Let point $P$ is $(1,-1,2)$ and point $Q$ is $(2,-1,3)$ $\Rightarrow$ Position vector of $P$ w.r.t. $Q$ is
$\begin{aligned}
& \vec{r}=(1-2) \hat{i}+(-1+1) \hat{j}+(2-3) \hat{k} \\
& \Rightarrow \vec{r}=-\hat{i}+0 \hat{j}-\hat{k} \text { and } \vec{F}=3 \hat{i}+2 \hat{j}-4 \hat{k} \\
& \Rightarrow \text { Moment }=\vec{r} \times \vec{F}=\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
-1 & 0 & -1 \\
3 & 2 & -4
\end{array}\right| \\
& =\hat{i}(0+2)-\hat{j}(4+3)+\hat{k}(-2+0)=2 \hat{i}-7 \hat{j}-2 \hat{k}
\end{aligned}$
Hence, the correct answer is option: 'C'.