Q101 / 160 · JIPMER 2007 · Physics

A force $F$ acting on an object varies with distance $x$ as shown here. The force is in newton and distance is in metre. The work done by the force in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is Figure

  • A
    4.5 J
  • Correct answer
    B
    13.5 J
  • C
    9.0 J
  • D
    18.0 J

Solution

The work done will be the area of the $F$-x graph. Work done in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is given by $W=$ area of rectangle + area of triangle $\begin{aligned} & =3 \times 3+\frac{1}{2} \times 3 \times 3 \\ & =9+4.5=13.5 \mathrm{~J}\end{aligned}$

Hence, the correct answer is option: 'B'.

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