Q92 / 160 · JIPMER 2012 · Physics
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
- A225 J
- Correct answerB200 J
- C400 J
- D175 J
Solution
Work done $W=$ Area $A B C D E F G A$
$=$ Area $A B C D G+$ Area $D E F G$
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$Hence, the correct answer is option: 'B'.