Q175 / 200 · Manipal (MET) 2010 · Physics
A disc of radius 0.1 m is rotating with a frequency $10 \mathrm{rev} / \mathrm{s}$ in a normal magnetic field of strength 0.1 T . Net induced emf is
- A$2 \pi \times 10^{-2} V$
- Correct answerB$\pi \times 10^{-2} \mathrm{~V}$
- C$\frac{\pi}{2} \times 10^{-2} \mathrm{~V}$
- DNone of these
Solution
Net induced emf due to disc is
$\begin{aligned} \varepsilon & =\frac{1}{2} B \omega l^2 \\ & =\frac{1}{2} \times 0.1 \times 2 \pi \times 10 \times 0.1 \times 0.1 \\ & =\pi \times 10^{-2} \mathrm{~V}\end{aligned}$
Hence, the correct answer is option: 'B'.