A bullet comes out of the barrel of gun of length 2 m with a speed 80 ~m / s . The average acceleration of the bullet is

Correct answer: (C) 1600 ~m / s^2. Given, s=2 ~m, u=80 ~m / s, v=0 From v^2=u^2-2 a s ∴ (0)^2=(80)^2-2 × a × 2 or a=(80 × 80)/4=1600 ~m / s^2

Q174 / 200 · Manipal (MET) 2010 · Physics

A bullet comes out of the barrel of gun of length 2 m with a speed $80 \mathrm{~m} / \mathrm{s}$. The average acceleration of the bullet is

A
$1.6 \mathrm{~m} / \mathrm{s}^2$
B
$160 \mathrm{~m} / \mathrm{s}^2$
Correct answer
C
$1600 \mathrm{~m} / \mathrm{s}^2$
D
$16 \mathrm{~m} / \mathrm{s}^2$

Solution

Given, $s=2 \mathrm{~m}, u=80 \mathrm{~m} / \mathrm{s}, v=0$ From $v^2=u^2-2 a s$ $\therefore (0)^2=(80)^2-2 \times a \times 2$ or $a=\frac{80 \times 80}{4}=1600 \mathrm{~m} / \mathrm{s}^2$

Hence, the correct answer is option: 'C'.

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