Q88 / 180 · JIPMER 2016 · Physics
A cylinder of radius $R$ and length $L$ is placed in a uniform electric field $E$ parallel to the cylinder axis. The total flux for the surface of the cylinder is given by
- A$2 \pi R^2 E$
- B$\frac{\pi R^2}{E}$
- C$\frac{R}{E}$
- Correct answerDzero
Solution
Flux through surface $A$,
$\begin{aligned} & \phi_A=E \times \pi R^2 \\ & \phi_B=-E \times \pi R^2\end{aligned}$
Flux through curved surface, $C=\int E \cdot d S$
$=\int E d S \cos 90^{\circ}=0$
$\therefore$ Total flux through cylinder $=\phi_A+\phi_B+\phi_C=0$
Flux through curved surface, $C=\int E \cdot d S$
$=\int E d S \cos 90^{\circ}=0$
$\therefore$ Total flux through cylinder $=\phi_A+\phi_B+\phi_C=0$Hence, the correct answer is option: 'D'.