Q109 / 160 · JIPMER 2010 · Physics

A charge $q$ is located at the centre of a cube. The electric flux through any face is

  • Correct answer
    A
    $\frac{4 \pi q}{6\left(4 \pi \varepsilon_0\right)}$
  • B
    $\frac{\pi q}{6\left(4 \pi \varepsilon_0\right)}$
  • C
    $\frac{q}{6\left(4 \pi \varepsilon_0\right)}$
  • D
    $\frac{2 \pi q}{6\left(4 \pi \varepsilon_0\right)}$

Solution

According to Gauss's theorem, electric flux through the cube (closed surface), $\phi=\frac{q}{\varepsilon_0}$ Since, cube has six surfaces and all the faces are symmetrical, therefore electric flux through any face $\phi^{\prime}=\frac{q}{6 \varepsilon_0}=\frac{4 \pi q}{6\left(4 \pi \varepsilon_0\right)}$

Hence, the correct answer is option: 'A'.

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