A current of $0.1$ A flows through a $25 ~\Omega$ resistor represented by the circuit diagram. The current in the $80 ~\Omega$ resistor is

• A

  $0.1 \mathrm{~A}$
• B

  $0.2 \mathrm{~A}$
• Correct answer
  C

  $0.3 \mathrm{~A}$
• D

  $0.4 \mathrm{~A}$

Solution

$0.1 \times\left(25+\frac{20 \times 60}{20+60}\right)=i_{2} \times 20$ $I_{2}=0.2 \mathrm{~A}$ Hence, $\mathrm{i}$ through $80 \Omega$ $0.1+0.2=0.3 \mathrm{~A}$

Hence, the correct answer is option: 'C'.