Q103 / 160 · JIPMER 2012 · Physics

A current of 1.6A is passed through a solution of $\mathrm{CuSO}_4$. How many $\mathrm{Cu}^{++}$ions are liberated in one minute? (Electronic charge $=1.6 \times 10^{-19} \mathrm{C}$ )

  • Correct answer
    A
    $3 \times 10^{20}$
  • B
    $3 \times 10^{10}$
  • C
    $6 \times 10^{20}$
  • D
    $6 \times 10^{10}$

Solution

Charge flowing in one minute $q=I \times t=1.6 \times 60 \mathrm{C}$ Charge required to liberate one copper ion 2 C Number of $\mathrm{Cu}^{2+}$ liberated $=\frac{1.6 \times 60}{2 \times 1.6 \times 10^{-19}}$ $=3 \times 10^{20}$

Hence, the correct answer is option: 'A'.

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