A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm . If the density of the substance in the crystal…

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A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm . If the density of the substance in the crystal is 8 g cm^(-3), then the number of atoms present in 256 g of the crystal is N × 10^24 . The value of N is

MARKS Content Team · Accepted Answer

Correct answer: 2. Formula of density =(Z×M)/(N_A×a^3) For FCC unit cell Z,=4 Edge length, a=4×10^(-8) cm M=(d×N_A×a^3)/Z=(8×6×10^23×64×10^(-24))/4 g/mol Number of atoms =wtg/(molar mass)×N_A=(256×10×6×10^23)/(8×6×16)=2×10^24 Hence, the required value of N = 2

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of $400 pm$ . If the density of the substance in the crystal is $8 g {cm}^{- 3},$ then the number of atoms present in $256 g$ of the crystal $is N \times 10^{24}$ . The value of $N$ is

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Relevant Questions

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm . If the density of the substance in the crystal is 8 g cm-3, then the number of atoms present in 256 g of the crystal is N × 1024 . The value of N is

Solution

Relevant Questions

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of $400 pm$ . If the density of the substance in the crystal is $8 g {cm}^{- 3},$ then the number of atoms present in $256 g$ of the crystal $is N \times 10^{24}$ . The value of $N$ is