Q36 / 150 · MHT CET 2022 (07 Aug Shift 2) · Chemistry

A conductivity cell has two electrodes $18 \mathrm{~mm}$ apart and having cross sectional area $2.0 \mathrm{~cm}^2$. What is value of cell constant?

  • Correct answer
    A
    $0.9 \mathrm{~cm}^{-1}$
  • B
    $0.18 \mathrm{~cm}^{-1}$
  • C
    $3.6 \mathrm{~cm}^{-1}$
  • D
    $0.2 \mathrm{~cm}^{-1}$

Solution

Cell constant $=\frac{\mathrm{L}}{\mathrm{A}}=\frac{1.8}{2}=0.9 \mathrm{~cm}^{-1}$

Hence, the correct answer is option: 'A'.

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