Q39 / 150 · MHT CET 2024 (10 May Shift 1) · Chemistry

A conductivity cell dipped in 0.05 M KCl has resistance 600 ohm . If conductivity is $0.0012 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. What is the value of cell constant?

  • A
    $0.50 \mathrm{~cm}^{-1}$
  • Correct answer
    B
    $0.72 \mathrm{~cm}^{-1}$
  • C
    $1.5 \mathrm{~cm}^{-1}$
  • D
    $2.0 \mathrm{~cm}^{-1}$

Solution

$\begin{aligned} & \text { Conductivity }(\mathrm{k})=\frac{\text { Cell constant }}{\mathrm{R}} \\ \therefore \quad & \text { Cell constant }=\mathrm{k} \times \mathrm{R} \\ = & 0.0012 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1} \times 600 \mathrm{ohm}=0.72 \mathrm{~cm}^{-1}\end{aligned}$

Hence, the correct answer is option: 'B'.

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