Q20 / 117 · NTA Abhyas (NEET) 2020 · Physics · Alternating Current

A charged capacitor $C = 30 μF$ is connected to an inductor $L = 27 mH$ , then the angular frequency of the system is

A
$9 .1 \times 10^{3} rad s^{- 1}$
B
$3 \times 10^{3} rad s^{- 1}$
Correct answer
C
$1.1 \times 10^{3} rad s^{- 1}$
D
$0.3 \times 10^{3} rad s^{- 1}$

Solution

Given,

C = 30 μ F, = 30 \times 10^{- 6} F, L = 27 m H = 27 \times 10^{- 3} H

Since, we know, angular frequency,

ω = \frac{1}{\sqrt{L C}} = \frac{1}{\sqrt{27 \times 10^{- 3} \times 30 \times 10^{- 6}}}

= \frac{1}{9 \times 10^{- 4}}

=

1.1 \times 10^{3} rad s^{- 1}

Hence, the correct answer is option: 'C'.

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