Q4 / 117 · NTA Abhyas (NEET) 2020 · Physics · Alternating Current

A 100 V, AC source of frequency 500 Hz is connected to an LCR circuit with L=8.1 mH, C = 12.5 µF, R = 10 Ω all connected in series as shown in the figure. What is the quality factor of the circuit?

Figure

  • A
    2.02
  • Correct answer
    B
    2.54
  • C
    50.54
  • D
    200.54

Solution

In the condition of resonance , quality factor

Q=1RLC = 110 8.1×10-312.5×10-6

=2.54

Hence, the correct answer is option: 'B'.

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