Q189 / 200 · Manipal (MET) 2013 · Physics
A charge $q$ is located at the centre of a cube. The electric flux through any face is
- A$\frac{\pi q}{6\left(4 \pi \varepsilon_0\right)}$
- B$\frac{q}{6\left(4 \pi \varepsilon_0\right)}$
- C$\frac{2 \pi q}{6\left(4 \pi \varepsilon_0\right)}$
- Correct answerD$\frac{4 \pi q}{6\left(4 \pi \varepsilon_0\right)}$
Solution
Gauss's law
$\phi=\frac{q}{\varepsilon_0}$
$\phi^{\prime}=\frac{\phi}{6}=\frac{q}{6 \varepsilon_0}=\frac{4 \pi q}{6\left(4 \pi \varepsilon_0\right)}$
Hence, the correct answer is option: 'D'.