Q40 / 50 · Manipal (MET) 2022 · Physics
The potential at a point at a distance $r$ from the centre of an electric dipole is proportional to
- A$\frac{1}{r}$
- Correct answerB$\frac{1}{r^2}$
- C$\frac{1}{r^3}$
- D$r^2$
Solution
The electric potential due to an electric dipole at a distance $r$ from its centre is given by
$\begin{aligned}
& { } 1 \mathrm{~V}=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{p \cos \theta}{r^2} \\
& \text { [where, } p=\text { electric dipole moment] }
\end{aligned}$
$\therefore \quad V \propto \frac{1}{r^2}$
Hence, the correct answer is option: 'B'.