A body weight W, is projected vertically upwards from earth's surface to reach a height above the earth which is equal to nine times the radius of…

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A body weight W, is projected vertically upwards from earth's surface to reach a height above the earth which is equal to nine times the radius of earth. The weight of the body at that height will be:

MARKS Content Team · Accepted Answer

Correct answer: (B) W/100. Final distance from the centre of earth wil be R+9R=10R. Now acceleration due to gravity at any height(distance from centre r) is given by, g=(GMr^2.Therefore,g^(')=GM10R^2Now, value of g at surface will be, GMR^2.Hence,g^(')=g100.Then, W^(')=mg^(')=mg)/100=W/100

A body weight $W$ , is projected vertically upwards from earth's surface to reach a height above the earth which is equal to nine times the radius of earth. The weight of the body at that height will be:

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