Q126 / 160 · AP EAMCET 2023 (16 May Shift 2) · Physics

A body of mass $10 \mathrm{~g}$ is tied to a string of length $0.4 \mathrm{~m}$ and it is whirled in a horizontal plane with a speed of $6 \mathrm{~ms}^{-1}$. Then the tension in the string is

  • A
    $1.9 \mathrm{~N}$
  • B
    $36 \mathrm{~N}$
  • Correct answer
    C
    $0.9 \mathrm{~N}$
  • D
    $3.6 \mathrm{~N}$

Solution

Mass of body, $\mathrm{m}=\log =10 \times 10^{-3} \mathrm{~kg}$ length of string, $\mathrm{L}=0.4 \mathrm{~m}$ speed, $v=6 \mathrm{~m} / \mathrm{s}$ In horizontal plane Tension, $\mathrm{T}=\frac{\mathrm{mv}^2}{\mathrm{r}}$ Here, length of string $=$ radius of string $\mathrm{T}=\frac{10^{-2} \times(6)^2}{0.4}=0.9 \mathrm{~N}$

Hence, the correct answer is option: 'C'.

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