Q124 / 160 · AP EAMCET 2023 (17 May Shift 2) · Physics
A body is moving with a uniform speed of $20 \mathrm{~ms}^{-1}$ on a horizontal circle. The change in velocity of the body in half revolution is
- A$20 \mathrm{~ms}^{-1}$
- B$10 \mathrm{~ms}^{-1}$
- Correct answerC$40 \mathrm{~ms}^{-1}$
- D$\frac{20}{\sqrt{2}} \mathrm{~ms}^{-1}$
Solution
Speed of body, $v=20 \mathrm{~m} / \mathrm{s}$ Change in velocity in half revolution

$\begin{aligned} & \Delta v=\vec{v}_2-\vec{v}_1=-v \hat{j}-v \hat{j}=-2 v \hat{j} \\ & |\Delta v|=2 v=2 \times 20=40 \mathrm{~m} / \mathrm{s}\end{aligned}$

$\begin{aligned} & \Delta v=\vec{v}_2-\vec{v}_1=-v \hat{j}-v \hat{j}=-2 v \hat{j} \\ & |\Delta v|=2 v=2 \times 20=40 \mathrm{~m} / \mathrm{s}\end{aligned}$
Hence, the correct answer is option: 'C'.