Q30 / 103 · NTA Abhyas (NEET) 2020 · Physics · Motion In One Dimension

A body moving in a straight line with constant acceleration covers distances a and b in successive equal time interval of t. The acceleration of the body is

  • A
    a+bt2
  • Correct answer
    B
    b-at2
  • C
    2b-a2t2
  • D
    b-2at2

Solution

a=ut+12  At2
b=(u+At)×t+12At2
⇒    A=(b-a)t2

Hence, the correct answer is option: 'B'.

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