Q14 / 46 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In One Dimension

A body is moving from rest under constant acceleration and let S1 be the displacement in the first P-1 seconds and S2 be the displacement in the first P seconds. The displacement in P2-P+1th second will be

  • Correct answer
    A
    S1+S2
  • B
    S1S2
  • C
    S1-S2
  • D
    None of these

Solution

From the equation of motion

                S=ut+12 at2

               S1=0+12 aP-12

And        S2=0+12 aP2

From      Sn=u+a22n-1

 SP2-P+1th=a22P2-P+1-1

                   =a22P2-2P+1=S1+S2

Hence, the correct answer is option: 'A'.

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