Q186 / 225 · JEE Main 2002 · Physics

A ball whose kinetic energy is E, is projected at an angle of $45^{\circ}$ to the horizontal. The kinetic energy of the ball at the highest point of its flight will be

  • A
    $\mathrm{E}$
  • B
    $\mathrm{E} / \sqrt{2}$
  • Correct answer
    C
    $E / 2$
  • D
    zero

Solution

As the velocity at the highest point reduces to zero. The K.E. of the ball also becomes zero.

Hence, the correct answer is option: 'C'.

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