A 800 turn coil of the effective area 0.05 m^2 is kept perpendicular to the magnetic field 5×10^(-5) T. When the plane of the coil is rotated by 90^o…

Question

A 800 turn coil of the effective area 0.05 m^2 is kept perpendicular to the magnetic field 5×10^(-5) T. When the plane of the coil is rotated by 90^o around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

MARKS Content Team · Accepted Answer

Correct answer: (D) 0.02 V. By Faraday's law, induced EMF in coil is equal to rate of change of magnetic flux linked with coil so ε=-(∆ϕ)/(∆t)=-(ϕ_f-ϕ_i)/(∆t)=-(0-NBA)/(∆t) =(800×5×10^(-5)×0.05)/0.1 =0.02 V

A $800$ turn coil of the effective area $0.05 m^{2}$ is kept perpendicular to the magnetic field $5 \times 10^{- 5} T .$ When the plane of the coil is rotated by $90^{o}$ around any of its coplanar axis in $0.1 s,$ the emf induced in the coil will be:

Solution

Relevant Questions

A 800 turn coil of the effective area 0.05 m2 is kept perpendicular to the magnetic field 5×10-5 T. When the plane of the coil is rotated by 90o around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

Solution

Relevant Questions

A $800$ turn coil of the effective area $0.05 m^{2}$ is kept perpendicular to the magnetic field $5 \times 10^{- 5} T .$ When the plane of the coil is rotated by $90^{o}$ around any of its coplanar axis in $0.1 s,$ the emf induced in the coil will be: