A 6 volt battery is connected to the terminal of a three metre long wire of uniform thickness and resistance of 100 $\mathrm{ohm}$. The difference of potential between two points on the wire separated by a distance of $50 \mathrm{~cm}$ will be:

• A

  2 volt
• B

  3 volt
• Correct answer
  C

  1 volt
• D

  1.5 volt

Solution

$$ \begin{gathered} \therefore \text { Voltage on } 50 \mathrm{~cm}=\frac{6}{300} \times 50 \\ =1 \text { volt } \end{gathered} $$

Hence, the correct answer is option: 'C'.