A 3ml of solution was made by dissolving 20mg of protein at 0°C. The osmotic pressure of the resulting solution is 3.8 torr. The molecular weight of…

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A 3ml of solution was made by dissolving 20mg of protein at 0°C. The osmotic pressure of the resulting solution is 3.8 torr. The molecular weight of the protein is approximately (in g/mol)

MARKS Content Team · Accepted Answer

Correct answer: (C) 3×10^4. This question is based on osmosis and osmotic pressure. The excess pressure which must be applied to a solution to prevent the passage of solvent into it through a semi-permeable membrane. π=(W_Bx Rx T)/(VX M_B) M_B=(W_Bx R x T)/(VX π) M_B=(20 X0.083 x 273 )/(3 x 3.8)=3 x 10^4g mol^(-1)

A $3 ml$ of solution was made by dissolving $20 mg$ of protein at $0 ° C .$ The osmotic pressure of the resulting solution is $3.8$ torr. The molecular weight of the protein is approximately (in $g / mol$ )

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