The osmotic pressure (in atm) of an aqueous solution containing 0.01 mol of NaCl (degree of dissociation 0.94 ) and 0.03 mol of glucose in 500 mL at $27^{\circ} \mathrm{C}$ is $\left(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$

• Correct answer
  A

  $2.43$
• B

  $4.23$
• C

  $3.24$
• D

  $3.42$

Hence, the correct answer is option: 'A'.