Q21 / 90 · JEE Main 2022 (26 Jul Shift 2) · Chemistry

A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0.0125 m3 at 6 bar and 27 °C. The mass of helium in the mixture is ..... g.

(Given : R=8.3JK-1 mol-1 (Atomic masses of H and He are 1u and 4u, respectively)

Correct answer: 8

Solution

PV=nmixRT

nmix=6×12.50.083×300≈3

Out of total 3 moles Let mole of He=x

Mole of H2=3-x

Then total mass of the mixture will be = 4x+23-x=10

Number of moles of He gas x=2 mol

Mass of He= number of moles × molar mass = 8 g

Hence, the correct answer is 8.

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