Q47 / 160 · AP EAMCET 2008 · Mathematics

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is

  • A
    $18720$
  • B
    $18270$
  • Correct answer
    C
    $17280$
  • D
    $12780$

Solution

Required number of arrangements $$ \begin{aligned} & ={ }^6 P_5 \times 4 ! \\ & =720 \times 24 \\ & =17280 \end{aligned} $$

Hence, the correct answer is option: 'C'.

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