Q23 / 90 · JEE Main 2021 (26 Feb Shift 1) · Chemistry

$3.12 g$ of oxygen is adsorbed on $1.2 g$ of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at $1 atm$ and $300 K$ in $L$ is
$[R = 0.0821 L atm K^{- 1} {mol}^{- 1}]$

Correct answer: 2

Solution

$V = \frac{\frac{3.12}{32} \times 0.0821 \times 300}{1} = 2.40 L$

$∵ 1.2 gm$ adsorbs $2.40 L$

$∴ 1 gm$ adsorbs $2 L$

Hence, the correct answer is 2.

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