$2.5 \mathrm{g}$ of protein containing only glycine $\left({\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NO}}_2\right)$ is dissolved in water to make $500 \mathrm{mL}$ of solution. The osmotic pressure of this solution at $300 \mathrm{K}$ is found to be $5.03\times {10}^{-3}$ bar. The total number of glycine units present in the protein is

(Given : $\mathrm{R} = 0.083 \mathrm{L} \mathrm{bar} {\mathrm{K}}^{-1} {\mathrm{mol}}^{-1} )$

Hence, the correct answer is 330.