Q32 / 97 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solutions

2.0 molal aqueous solution of an electrolyte X2Y3 is 75% ionised. The boiling point of the solution a 1 atm is Kb(H2O)=0.52 K  kg  mol-1

  • A
    274.76 K
  • B
    377 K
  • C
    376.4 K
  • Correct answer
    D
    377.16 K

Solution

X2Y3(aq)→2X3+(aq)+3Y2-aq

n=5

ΔTb=i  Kb.m=(1+4α) Kbm

=(1+4×0.75)×0.52×2

=4.16; Tb=373+4.16=374.76

Hence, the correct answer is option: 'D'.

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