Q53 / 180 · NEET 2014 · Chemistry

$1.0 g$ of magnesium is burnt with $0.56 g$ $O_{2}$ in a closed vessel. Which reaction is left in excess and how much? (At, wt. $M g = 24; O = 16)$

Correct answer
A
$M g, 0.16 g$
B
$O_{2}, 0.16 g$
C
$M g, 0.44 g$
D
$O_{2}, O . 28 g$

Solution

M g + \frac{1}{2} O_{2} \to M g O

\frac{1.0}{24} \frac{0.56}{32}

\frac{0.5}{12} \frac{0.07}{4}

Oxygen is limiting reagent so

\frac{0.07}{4} - \frac{x}{2} = 0

x = \frac{0.07}{2}

excess

M g = \frac{0.5}{12} - \frac{0.07}{2}

mole
mass of

M g

is

= 1 - 0.7 \times 12 = 0.16 g r a m .

Hence, the correct answer is option: 'A'.

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